NEC Conductor Derating and Motor Continuous Load: Do the 80% Rules Stack?

NEC Conductor Derating and Motor Continuous Load: Do the 80% Rules Stack?

Electrician Questions is a technical series from ElectriciansX for licensed electricians, apprentices, and inspectors working in the field. These articles walk through NEC logic step by step — not homeowner summaries.

The question: If I run more than five current-carrying conductors in a raceway, I know I must derate per NEC Table 310.15(C)(1). If that circuit also feeds a motor on continuous duty — where conductors are sized at 125% of full-load current — does an additional “80% capacity” rule stack on top of the conduit derating? Using #12 THHN, five current-carrying conductors, and a continuous motor load of 14 amps, what is the correct math?

Short Answer

Yes, both requirements apply — but they are not the same 80% applied twice to one number.

  • Conduit derating (Table 310.15(C)(1)) reduces the ampacity you are allowed to use from the conductor.
  • Motor continuous-load sizing (430.22) increases the ampacity the conductor must carry to 125% of motor FLA.
  • The separate 80% OCPD rule (210.20(B) / 215.3) limits continuous load on a breaker — it does not replace or cancel conductor derating.

You compare: adjusted ampacity ≥ required ampacity. You do not multiply 0.80 × 0.80 on the same base ampacity unless you are incorrectly mixing unrelated rules.

The Three “80%” Ideas Electricians Mix Up

Rule NEC reference What it actually does
Conduit fill derating 310.15(C)(1) / Table 310.15(C)(1) 4–6 current-carrying conductors → multiply ampacity by 80%
Motor branch conductors 430.22 Continuous-duty motor → size conductors at 125% of FLA (inverse of “only use 80%”)
Continuous load on OCPD 210.20(B), 215.3 Non-motor continuous loads → load ≤ 80% of standard OCPD rating (unless 100%-rated device)

Motor branch circuits are primarily governed by Article 430, which has its own conductor and overcurrent rules. Do not apply 210.20(B) motor logic as if it were a second conductor derating factor.

NEC Table 310.16 — #12 THHN Copper (Selected Values)

THHN is rated 90°C dry. For ampacity selection, start with Table 310.16. Termination temperature limits in 110.14(C) may require using the 75°C column at equipment — we show both below.

Source: NFPA 70 (NEC) Table 310.16 — excerpt for 12 AWG copper THHN/THWN-2
Conductor 60°C 75°C 90°C
12 AWG copper 20 A 25 A 30 A

NEC Table 310.15(C)(1) — Adjustment Factors (4–6 Conductors)

Source: NFPA 70 (NEC) Table 310.15(C)(1) — adjustment factors for more than three current-carrying conductors
Current-carrying conductors Adjustment factor % of Table 310.16
4–6 0.80 80%
7–9 0.70 70%
10–20 0.50 50%
21–30 0.45 45%

Five current-carrying conductors → 80% adjustment factor. Equipment grounding conductors are not current-carrying. Ungrounded conductors count. Neutral conductors count when they carry unbalanced current per 310.15(C)(1) exception notes.

Visual: How Derating and Motor 125% Interact

#12 THHN — 5 current-carrying conductors — 14 A continuous motor
Base ampacity (90°C col.) ………. 30.0 A
× Derating factor ……………. × 0.80
Adjusted ampacity available ……. 24.0 A
Motor FLA …………………….. 14.0 A
× Continuous motor multiplier …. × 1.25 (430.22)
Required ampacity ……………. 17.5 A
Check: 24.0 A ≥ 17.5 A → #12 THHN is acceptable (90°C basis)

Worked Example — Step by Step

Given

  • Conductor: #12 THHN copper
  • Raceway: 5 current-carrying conductors in same conduit
  • Load: motor, continuous duty, 14 A FLA
  • Assume 90°C ampacity permitted for this calculation path

Step 1 — Required ampacity (motor load rule)

NEC 430.22 requires branch-circuit conductors supplying a single motor to have an ampacity not less than 125% of the motor full-load current for motors rated continuous.

Irequired = 14 A × 1.25 = 17.5 A

Step 2 — Adjusted ampacity (derating rule)

From Table 310.16 (90°C): #12 = 30 A. From Table 310.15(C)(1) for 5 CCC: factor = 0.80.

Iadjusted = 30 A × 0.80 = 24 A

Step 3 — Compare

Per 310.15(A) and general sizing practice: adjusted ampacity must be ≥ required ampacity.

24 A ≥ 17.5 A → PASS

Step 4 — 75°C termination check (often decisive in the field)

If motor starter terminals are rated 75°C (common), 110.14(C)(1)(a) may limit you to the 75°C column before derating:

Iadjusted,75°C = 25 A × 0.80 = 20 A
20 A ≥ 17.5 A → still PASS for this example

Comparison Chart — Where #12 Would Fail

Motor FLA (continuous) Required (×1.25) #12 adj. @90°C (24 A) #12 adj. @75°C (20 A) Result
14 A 17.5 A 24 A 20 A OK
16 A 20.0 A 24 A 20 A OK at limit (75°C)
17 A 21.25 A 24 A 20 A FAIL @75°C → use #10
20 A 25.0 A 24 A 20 A FAIL → use #10

Bar Graph — Required vs Available Ampacity (14 A Motor)

17.5 A
Required
(14×1.25)
24 A
Adjusted
(30×0.80)
20 A
Adjusted @75°C
(25×0.80)

Scale: 1 px ≈ 0.12 A. All three bars exceed the 17.5 A requirement for a 14 A continuous motor.

What About the Breaker “80% Rule”?

210.20(B) states that continuous loads on overcurrent devices (other than motor-specific applications covered by Article 430) shall not exceed 80% of the device rating. That governs breaker loading, not conductor ampacity derating.

For motors, overcurrent protection follows 430.52 (inverse-time breaker typically up to 250% of FLA per table, subject to exceptions). A 14 A motor does not get sized by “putting 14 A on a 20 A breaker at 80%.” The motor article is separate.

Common Mistakes in the Field

  • Multiplying 0.80 × 0.80 on 30 A because “motor is continuous” — the 125% is applied to load, not as a second derate on ampacity.
  • Skipping derating because “it is only a 14 A motor on #12” — five CCC still forces Table 310.15(C)(1).
  • Using 30 A and calling it a 20 A circuit because of an old “#12 = 20 A” rule of thumb — 240.4(D) small-conductor rules and motor exceptions still require the ampacity calculation above.
  • Ignoring 75°C termination limits at contactors and panels — especially on commercial jobs in Southwest Florida.

Inspector / Foreman Quick Checklist

  1. Count current-carrying conductors in the raceway segment.
  2. Look up base ampacity — Table 310.16 at correct temperature column.
  3. Apply adjustment factors — Table 310.15(C)(1), plus ambient if needed.
  4. Calculate required ampacity — 125% motor FLA for continuous (430.22).
  5. Verify Iadjusted ≥ Irequired.
  6. Size OCPD per Article 430 — not 210.20(B).

Bottom Line for This Example

With #12 THHN, five current-carrying conductors, and a 14 A continuous motor:

  • Derated ampacity: 24 A (90°C) or 20 A (75°C)
  • Required ampacity: 17.5 A
  • #12 is code-compliant for ampacity in this scenario

The derating and the motor continuous factor both apply, but they work on opposite sides of the inequality — not as two stacked discounts on the same number.

References: NFPA 70 (NEC) Articles 110, 210, 310, 430 — Tables 310.16 and 310.15(C)(1). Values shown reflect commonly adopted editions (2020/2023). Always verify the edition adopted by your AHJ. This article is educational and does not replace the official NEC text or local amendments.

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ElectriciansX Team
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